z(2z+3)=2z^2+3z-7

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Solution for z(2z+3)=2z^2+3z-7 equation:


Simplifying
z(2z + 3) = 2z2 + 3z + -7

Reorder the terms:
z(3 + 2z) = 2z2 + 3z + -7
(3 * z + 2z * z) = 2z2 + 3z + -7
(3z + 2z2) = 2z2 + 3z + -7

Reorder the terms:
3z + 2z2 = -7 + 3z + 2z2

Add '-3z' to each side of the equation.
3z + -3z + 2z2 = -7 + 3z + -3z + 2z2

Combine like terms: 3z + -3z = 0
0 + 2z2 = -7 + 3z + -3z + 2z2
2z2 = -7 + 3z + -3z + 2z2

Combine like terms: 3z + -3z = 0
2z2 = -7 + 0 + 2z2
2z2 = -7 + 2z2

Add '-2z2' to each side of the equation.
2z2 + -2z2 = -7 + 2z2 + -2z2

Combine like terms: 2z2 + -2z2 = 0
0 = -7 + 2z2 + -2z2

Combine like terms: 2z2 + -2z2 = 0
0 = -7 + 0
0 = -7

Solving
0 = -7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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